1.4 Lösning 9b
Från Mathonline
\( \left({a^2 - 6\,a + 9 \over b^6}\right)\, \Big / \,\left({a - 3 \over b^5}\right) \, = \, \left({a^2 - 6\,a + 9 \over b^6}\right)\, \cdot \,\left({b^5 \over a - 3}\right) \, = \, \)
\( = \, {(a-3)^2 \over b^6}\, \cdot \,{b^5 \over a - 3} \, = \, {(a-3)^2 \cdot b^5 \over b^6 \cdot (a - 3)} \, = {a-3 \over b} \)
