1.4 Lösning 8c

Vi sätter in \( x=2\, \) i ekvationen\[ \begin{align} {15\cdot 2^2 - 2\cdot 2 - 6 \over 6} & = {2 - 3\,z \over 2} - {z - 2\cdot 2^2 \over 3} - {z \over 2} \\ {15\cdot 4 - 4 - 6 \over 6}& = {2 - 3\,z \over 2} - {z - 2\cdot 4 \over 3} - {z \over 2} \\ {60 - 4 - 6 \over 6} & = {2 - 3\,z \over 2} - {z - 8 \over 3} - {z \over 2} \\ {50 \over 6} & = {2 - 3\,z \over 2} - {z - 8 \over 3} - {z \over 2} \\ {25 \over 3} & = {2 - 3\,z \over 2} - {z - 8 \over 3} - {z \over 2} \quad & &\,| \; \cdot 6 \\ 50 & = 3\,(2 - 3\,z) - 2\,(z - 8) - 3\,z \\ 50 & = 6 - 9\,z - 2\,z + 16 - 3\,z \\ 50 & = - 14\,z + 22 \\ \end{align} \]