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		<id>https://matte5.mathonline.se/index.php?action=history&amp;feed=atom&amp;title=1.5_L%C3%B6sning_1c</id>
		<title>1.5 Lösning 1c - Versionshistorik</title>
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		<updated>2026-07-23T13:47:03Z</updated>
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		<id>https://matte5.mathonline.se/index.php?title=1.5_L%C3%B6sning_1c&amp;diff=3011&amp;oldid=prev</id>
		<title>Taifun: Created page with &quot;&lt;math&gt; (25\,x^2)^{1/2} = 25^{1/2} \cdot (x^2)^{1/2} = \sqrt{25} \cdot x^{2\cdot {1 \over 2}} = 5 \cdot x^1 = 5\,x &lt;/math&gt;&quot;</title>
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				<updated>2011-03-09T22:16:52Z</updated>
		
		<summary type="html">&lt;p&gt;Created page with &amp;quot;&amp;lt;math&amp;gt; (25\,x^2)^{1/2} = 25^{1/2} \cdot (x^2)^{1/2} = \sqrt{25} \cdot x^{2\cdot {1 \over 2}} = 5 \cdot x^1 = 5\,x &amp;lt;/math&amp;gt;&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;Ny sida&lt;/b&gt;&lt;/p&gt;&lt;div&gt;&amp;lt;math&amp;gt; (25\,x^2)^{1/2} = 25^{1/2} \cdot (x^2)^{1/2} = \sqrt{25} \cdot x^{2\cdot {1 \over 2}} = 5 \cdot x^1 = 5\,x &amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Taifun</name></author>	</entry>

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